Check if String contains Characters from a Defined Set

Letters

let letters = CharacterSet.letters

let phrase = "Test case"
let range = phrase.rangeOfCharacter(from: letters)

// range will be nil if no letters is found
if let test = range {
   print("letters found")
}
else {
   print("letters not found")
}

let letters = NSCharacterSet.letterCharacterSet()

let phrase = "Test case"
let range = phrase.rangeOfCharacterFromSet(letters)

// range will be nil if no letters is found
if let test = range {
   print("letters found")
}
else {
  print("letters not found")
}

The new CharacterSet struct that is also bridged to the Objective-C NSCharacterSet class define several predefined sets as:

decimalDigits
capitalizedLetters
alphanumerics
controlCharacters
illegalCharacters
and more you can find in the NSCharacterSet reference.

You also can define your own set of characters:

let phrase = "Test case"
let charset = CharacterSet(charactersIn: "t")

if let _ = phrase.rangeOfCharacter(from: charset, options: .caseInsensitive) {
   print("yes") 
}
else {
   print("no")
}

let charset = NSCharacterSet(charactersInString: "t")

if let _ = phrase.rangeOfCharacterFromSet(charset, options: .CaseInsensitiveSearch, range: nil) {
   print("yes")
}
else {
    print("no")
}

You can also include range:

let phrase = "Test case"
let charset = CharacterSet(charactersIn: "t")

if let _ = phrase.rangeOfCharacter(from: charset, options: .caseInsensitive, range: phrase.startIndex..<phrase.endIndex)) {
   print("yes") 
}
else {
   print("no")
}

Found a mistake? Have a question or improvement idea? Let me know.

Table Of Contents